Q1. Quantity
I:’x’ -. Two circles are concentric with center ‘O’.
Their radii are 8cm and 10cm respectively. ‘B’ and ‘C’ are
the points of contact of two tangents drawn from bigger circle to
smaller circle from point ‘A’ lying on bigger circle. ‘x’ is
area of quadrilateral ABOC formed in cm^2
Quantity II: -
‘y’ - The lengths of two parallel sides of a trapezium
are 6 cm and 8 cm. If the height of the trapezium be 6 cm, then its
area is ‘y’ cm^2
(a) Quantity I > Quantity
II
(b) Quantity I < Quantity II
(c) Quantity I ≥
Quantity II
(d) Quantity I ≤ Quantity II
(e) Quantity I =
Quantity II or No relation
Q2. Quantity I: ‘x’ -.
Kundan invested Rs. 20,000 in a scheme offering 22% p.a. at Simple
interest. After 2 years he withdraws his money and invested in a bank
which is offering ‘x%’ p.a. at compound interest. After 3 years,
interest earned by him is Rs.1350 less than amount invested by him in
this bank.
Quantity II: - ‘y’ – Bhawesh sells a
diary at Marked price and earns 85 (5/7) % profit while if he gives
'y%’ discount on Marked price then he will earn ‘y%’
profit.
(a) Quantity I > Quantity II
(b)
Quantity I < Quantity II
(c) Quantity I ≥ Quantity II
(d)
Quantity I ≤ Quantity II
(e) Quantity I = Quantity II
or No relation
Q3. Quantity I—‘x’: P alone can do
the work in ‘x’ days. Q can complete a work in 5 more days than P
while Q does the same work in 9 more days than R. If Q and P can
complete the whole work in same time as time taken by R alone to do
the whole work.
Quantity II —‘y’: ‘y’ is the
days taken by 8 men and 14 women to reap 7/12 part of
360-hectare land by working 7 hrs per day if 6 men and 10 women can
reap 5/12 part of the land in 15 days by working 6 hrs per day. It is
also given that work of 2 men is equal to that of 3 women.
(a)
Quantity I > Quantity II
(b) Quantity I < Quantity
II
(c) Quantity I ≥ Quantity II
(d) Quantity I ≤
Quantity II
(e) Quantity I = Quantity II or No relation
Q4.
Quantity I — ‘x’: ‘x’ is the difference between the speeds
of X and Y. Distance between P and Q is 60 km. X and Y start from P
at same time & meet 1st time at a place 12 km from Q. They return
to P immediately after reaching Q. The speed of slower person is 48
km/hr.
Quantity II —‘y’: ‘y’ is the average speed of
train if a distance of 600 km is to be covered in 2 parts. In 1st
phase 120 km is traveled by train and rest by car and it took total
of 8 hrs, but if 200 km is covered by train and rest by car it takes
20 min more.
(a) Quantity I > Quantity II
(b)
Quantity I < Quantity II
(c) Quantity I ≥ Quantity II
(d)
Quantity I ≤ Quantity II
(e) Quantity I = Quantity II or No
relation
Q5. Average of any 200 consecutive natural
numbers is 499.5. If next 1000 numbers more are added in it then find
the new average.
(a) 1035.5
(b) 1299.5
(c)
1199.5
(d) 1099.5
(e) 999.5
Solutions (1-5):
Direction
(6-10): - Line chart given below shows time taken by five different
students to complete an assignment ‘M’ alone. Ratio of efficiency
of all five students remain same throughout any work. Study the data
carefully and answer the following questions.
Q6. All five
starts working together to complete work ‘X’. ‘Vivek’ left
after 8 days. Work done by ‘Bhawesh’ is same as work done by
‘Nitin’ while ‘Anurag’ and ‘Nitin’ worked for same time.
‘Swati’ worked for ‘y’ days. If ‘Bhawesh’, ‘Nitin’
and ‘Swati’ together can complete work ‘X’ in 24 days then
find the value of ‘y’ if Bhawesh worked for starting 10
days.
(a) 7 days
(b) 9 days
(c) 11 days
(d)
13 days
(e) 15 days
Q7. Anurag and Nitin together can
complete work ‘Z’ in (A + 42) days while Bhawesh and Swati
together can complete work ‘Z’ in (A + 15) days. All start the
work Z such that ratio between work done by Anurag, Bhawesh and Vivek
is 1 : 2 : 3, while ratio between days, Nitin, Swati and Vivek worked
is 2 : 2 : 1. Find how many days ‘Bhawesh’ worked.
(a)
10 days
(b) 15 days
(c) 20 days
(d) 30 days
(e)
40 days
Q8. All five persons started together to complete
work ‘Y’. Vivek worked for starting 6 days and left the work.
After 3 days more both Bhawesh and Swati left too. Remaining 40% work
should be completed by Anurag and Nitin together but ‘Anurag’
left after ‘x’ days. Remaining work is completed by ‘Nitin’
in ‘z’ days. If ‘z – x = 3’, then number of days for which
‘Nitin’ worked is what percent more than number of days for which
‘Anurag’ worked.
(a) 100/3%
(b) 50%
(c)
200/3%
(d) 75%
(e) 100%
Q9. Anurag, Bhawesh and
Nitin together starts to do work ‘M’. After 7 days ‘Nitin’
left and after 3 days more ‘Anurag’ and ‘Bhawesh’ left.
Remaining work is completed by Swati and Vivek working alternatively
in ‘y’ days. If ‘y’ is integer, then find ‘Vivek’ worked
for how many days?
(a) 3 days
(b) 5 days
(c) 4
days
(d) 6 days
(e) Cannot be determined
Q10.
Anurag, Bhawesh and Swati starts working together to complete work
‘M’. After 5 days, Bhawesh and Swati replaced by Nitin and Vivek.
After 5 more days Anurag left the work. After 1 more day Vivek left
too. Nitin worked for total ‘x’ days. In other case Anurag and
Bhawesh starts working together to complete ‘M’. After 4 days
both are replaced by Vivek. Vivek worked for 5 days and replaced by
Swati who worked for 8 days. Remaining work is completed by Nitin in
‘y’ days. Find (y - x)2 ?
(a) 25
(b) 36
(c)
49
(d) 64
(e) 81
Solutions (6-10):
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